if a > 2b > 0 , then positive value of m...

if `a > 2b > 0` , then positive value of `m` for which `y=mx-bsqrt(1+m^2)` is a common tangent to `x^2 + y^2 =b^2` and `(x-a)^2+y^2=b^2` is

A

`( 2b ) /( sqrt( a^(2) - 4b^(2)))`

B

`( sqrt( a^(2) - 4b^(2)))/(2b)`

C

`(2b)/( a-2b)`

D

`(b)/(a-2b)`

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The correct Answer is:

A

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