Home
Class 12
MATHS
There are two circles whose equation are...

There are two circles whose equation are `x^2+y^2=9` and `x^2+y^2-8x-6y+n^2=0,n in Zdot` If the two circles have exactly two common tangents, then the number of possible values of `n` is 2 (b) 8 (c) 9 (d) none of these

A

2

B

8

C

9

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Similar Questions

Explore conceptually related problems

There are two circles whose equation are x^(2)+y^(2)=9 and x^(2)+y^(2)-8x-6y+n^(2)=0,n in Z. If the two circles have exactly two common tangents,then the number of possible values of n is 2 (b) 8 (c) 9 (d) none of these

If the two circles x^(2) + y^(2) =4 and x^(2) +y^(2) - 24x - 10y +a^(2) =0, a in I , have exactly two common tangents then the number of possible integral values of a is :

the no.of possible integral values of m for which the circle x^(2)+y^(2)=4 and x^(2)+y^(2)-6x-8y+m^(2)=0 has exactly two common tangents are

The two circles x^(2)+y^(2)-2x-3=0 and x^(2)+y^(2)-4x-6y-8=0 are such that

The number of common tangents to the circles x^(2)+y^(2)-y=0and x^(2)+y^(2)+y=0 is