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A tangent PT is drawn to the circle x^2+...

A tangent PT is drawn to the circle `x^2+y^2=4` at the point `P(sqrt3,1)`. A straight line `L`, perpendicular to `PT` is a tangent to the circle `(x-3)^2+y^2=1` then find a common tangent of the two circles

A

x=4

B

y = 2

C

`x + sqrt( 3) y = 4`

D

` x+ 2 sqrt( 2) y= 6`

Text Solution

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The correct Answer is:
D
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