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For some x in [-1, 1] we have cos^(-1)x...

For some `x in [-1, 1]` we have `cos^(-1)x =tan^(-1)x`.
The value of `x^(2) ` is :

A

`(sqrt(5)-1)/(2)`

B

`(sqrt(5)+1)/(2)`

C

`(sqrt(3)-1)/(2)`

D

`(sqrt(3)+1)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
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