Let m be the number of solutions of sin...

Let m be the number of solutions of `sin(2x)+cos(2x)+cosx+1=0` in `0 lt x lt (pi)/(2) and n = sin [tan^(-1)(tan((7pi)/(6)))+cos^(-1)(cos((7pi)/(3)))]`, then find the value of `(m^(2)+n^(2)+m+n+4)`

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