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In x epsilon(0,1),f(x)=[3x^(2)+1], where...

In `x epsilon(0,1),f(x)=[3x^(2)+1]`, where [x] stands for the greatest integer not exceeding x is:

A

continuous

B

continuous except at one point

C

continuous except at two points

D

continuous except at three points

Text Solution

Verified by Experts

The correct Answer is:
C
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