If y={log(cosx)sinx}"{"log(sinx)cosx")"^...

If `y={log_(cosx)sinx}"{"log_(sinx)cosx")"^(-1)+s in^(-1)((2x)/(1+x^2)),` find `(dy)/(dx)a tx=pi/4dot`

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The correct Answer is:

`(-8)/(log_(e)2+32/(16+pi^(2))`

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