If f(x)={xe^-[1/(|x|)+1/x]; x != 0; 0;x...

If `f(x)={xe^-[1/(|x|)+1/x]; x != 0; 0;x=0` Prove that `f(x)` is not differentiable at `x = 0`

Verified by Experts

The correct Answer is:

Yes, no

Similar Questions

Explore conceptually related problems

f(x)={-x;x 1 Prove that f(x) is not differentiable at x=0

If f(x)={:{(xe^(-(1/(|x|) + 1/x)), x ne 0),(0 , x =0 ):} then f(x) is

Prove that the function f(x)={x/(1+e^(1/x)); if x != 0 0; if x=0 is not differentiable at x = 0.

Prove that f(x)={x sin((1)/(x)),x!=0,0,x=0 is not differentiable at x=0

If f(x)={(x)/(1+e^((1)/(x))) for x!=0,0f or x=0 then the function f(x) is differentiable for

Let f(x)={(x^(p)"sin"1/x,x!=0),(0,x=0):} then f(x) is continuous but not differentiable at x=0 if

Let f(x)=(xe)^((1)/(|x|)+(1)/(x));x!=0,f(0)=0, test the continuity & differentiability at x=0