If the sum of the lengths of the hypotenues and a side of a right angled triangle is given, show that the area of the triangle is maximum when the angle between them is `pi//3` .

If the sum of the lengths of the hypotenuse and another side of a right-angled triangle is given,show that the area of the triangle is maximum when the angle between these sides is (pi)/(3).

If the sum of lengths of hypotenuse and a side of a right angled triangle is given,show that area of triangle is maximum,when the angle between them is (pi)/(3) .

If the sum of a side and hypotenuse of a right angled triangle is given then show that area of triangle will be maximum when the angle between side and the hypotenuse is pi//3 .

If the length of the hypotenuse of a right angled triangle is 10 cm, then what is the maximum area of such a right angled triangle?

In the right triangle BAC, angle A=pi/2 and a+b=8 . The area of the triangle is maximum when angle C , is

The lengths of the medians through acute angles of a right-angled triangle are 3 and 4. Find the area of the triangle.

Find the length of the hypotenuse in a right angled triangle where the sum of the squares of the sides making right angle is 169.

If the length of sides of right angled triangle are in AP, then their ratio is

The maximum area of a right angled triangle with hypotenuse h is