Let the function f(x) be defined as belo...

Let the function `f(x)` be defined as below `f(x)=sin^(-1) lambda+x^2` when `0 < x < 1` and `f(x) = 2x` when `x>=1` . `f(x)` can have a minimum at `x=1` then value of `lambda` is

Verified by Experts

The correct Answer is:

A

Similar Questions

Explore conceptually related problems

Let the function f(x) be defined as below f(x)=cos^(-1) mu+x^2 when 0 =1 . f(x) can have a local minimum at x=1 then value of mu is

Let the function f be defined by f(x)=((2x+1)/(1-3x)) then f^(-1)(x) is

Let a function f:(0,infty)to[0,infty) be defined by f(x)=abs(1-1/x) . Then f is

Let f(x) be a function defined as below : f(x)=sin(x^(2)-3x) ,x le 0 =6x+5x^(2), x gt 0 then at x=0 ,f(x)

Let a function f:(1, oo)rarr(0, oo) be defined by f(x)=|1-(1)/(x)| . Then f is

f(x)={[x]+[-x], where x!=2 and lambda where If f(x) is continuous at x=2 then,the value of lambda will be