Home
Class 12
MATHS
A curve with equation of the form y=a x^...

A curve with equation of the form `y=a x^4+b x^3+c x+d` has zero gradient at the point `(0,1)` and also touches the `x-` axis at the point `(-1,0)` then the value of `x` for which the curve has a negative gradient are: `xgeq-1` b. `x<1` c. `x<-1` d. `-1lt=xlt=1`

A

`x gt -1`

B

`x lt 1`

C

`x lt -1`

D

`-1 le x le 1`

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Similar Questions

Explore conceptually related problems

A curve with equation of the form y=ax^(4)+bx^(3)+cx+d has zero gradient at the point (0,1) and also touches the x- axis at the point (-1,0) then the value of x for which the curve has a negative gradient are: a.x>=-1 b.x<1 c.x<-1 d.-1<=x<=1

A curve with equation of the form y=ax^(4)+bx^(3)+cx+d has zero gradient at the point (0,1) and also touches the x -axis at the point (-1,0) then a=3 b.b=4 c.c+d=1 d.for x<-1, the curve has a negative gradient

A curve with equation of the form y=ax^(4)+bx^(3)+cx+d has zero gradient at the point (0,1) and also touches the x-axis at the point (-1,0) then a=3 (b) b=4c+d=1 for x<-1, the curve has a negative gradient

If the curve y=x^(2)+bx +c touches the line y = x at the point (1,1), then the set of values of x for which the curve has a negative gradient is

If the line x+y=0 touches the curve y=x^(2)+bx+c at the point x=-2 , then : (b,c)-=

Find the equation of the curve whose gradient at (x,y) is y/(2x) and which passes through the point (a,2a) .

If the curve y=ax^(3) +bx^(2) +c x is inclined at 45^(@) to x-axis at (0, 0) but touches x-axis at (1, 0) , then

The line (x)/(a)+(y)/(b)=1 touches the curve y=be^(-x//a) at the point