Let f(x)=sin^(3)x+lambda sin^(2)x where ...

Let `f(x)=sin^(3)x+lambda sin^(2)x` where
`-pi//2ltxltpi//2.` Find the intervals in which `lambda` should lie in order that f(x) has exactly one minimum.

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The correct Answer is:

`lambda in (-3/2, 3/2)`

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