If `|veca+vecb|=|veca-vecb|`, then the vectors `vecaandvecb` are orthogonal

If vecaxxvecb=vecc and vecbxxvecc=veca then a. veca,vecb,vecc are orthogonal in pairs and |veca|=|vecc|,|vecb|=1 b. veca,vecb,vecc are not orthogonal to each other c. veca,vecb,vecc are orthogonal in pairs but |veca|!=|vecc| d. veca,vecb,vecc are orthogonal but |vecb|=1 OR If vecaxxvecb=vecc,vecbxxvecc=veca , then

If |veca+vecb|=|veca-vecb|, (veca,vecb!=vec0) show that the vectors veca and vecb are perpendicular to each other.

The vector vecA and vecB are such that |vecA+vecB|=|vecA-vecB| . The angle between vectors vecA and vecB is -

Let veca and vecb be two non-zero vectors perpendicular to each other and |veca|=|vecb| . If |veca xx vecb|=|veca| , then the angle between the vectors (veca +vecb+(veca xx vecb)) and veca is equal to :

If veca and vecb are two vectors such that |veca xx vecb|= veca.vecb , then what is the angle between veca and vecb ?

Given : vecP=vecA+vecBandvecQ=vecA-vecB . If the magnitudes of vectors vecP and vecQ are equal, what is the angle between vectors vecAandvecB ?

If veca and vecb are unequal unit vectors such that (veca -vecb) xx [(vecb+veca) xx (2veca+vecb)]=veca+vecb , then angle theta between veca and vecb can be

If vecaxxvecb=vecc and vecbxxvecc=veca , show that veca,vecb,vecc are orthogonal in pairs. Also show that |vecc|=|veca| and |vecb|=1

Let veca and vecb be two vectors such that |2 veca + 3 vecb| = |3 veca + vecb| and the angle between veca and vecb is 60^(@) . If 1/8 veca is a unit vector, then |vecb| is equal to :