Home
Class 12
MATHS
If veca, vecb, vecc are non coplanar vec...

If `veca, vecb, vecc` are non coplanar vectors and `lamda` is a real number, then `[(lamda(veca+vecb), lamda^(2)vecb, lamdavecc)]=[(veca, vecb+vecc,vecb)]` for

A

no value of `lambda`

B

exactly one value of `lambda`

C

exactly two values of `lambda`

D

exactly three values of `lambda`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

If veca, vecb, vecc are non coplanar vectors and lamda is a real number, then the vectors veca+2vecb+3vecc, lamdavecb+4vec and (2lamda-1)vecc are non coplanar for

If veca,vecb,vecc are noncoplanar vectors and lamda is a real number, then the vectors veca+2vecb+3vecc, lamda vecb+4vecc and (2lamda-1)vecc are non coplanar of (A) all values of lamda (B) all except one values of lamda (C) all except two values of lamda (D) no value of lamda

If veca, vecb, vecc are non coplanar non null vectors such that [(veca, vecb, vecc)]=2 then {[(vecaxxvecb, vecbxxvecc, veccxxveca)]}^(2)=

If veca, vecb and vecc are unit coplanar vectors, then the scalar triple product [(2veca-vecb, 2vecb-vecc, 2vecc-veca)]=

If veca, vecb, vecc are three non-zero non-null vectors are vecr is any vector in space then [(vecb, vecc, vecr)]veca+[(vecc, veca, vecr)]vecb+[(veca, vecb, vecr)]vecc is equal to

If veca , vecb and vecc are non- coplanar vectors and veca xx vecc is perpendicular to veca xx (vecb xx vecc) , then the value of [ veca xx ( vecb xx vecc)] xx vecc is equal to

If veca, vecb, vecc are any three non coplanar vectors, then (veca+vecb+vecc).(vecb+vecc)xx(vecc+veca)

If veca, vecb, vecc , be three on zero non coplanar vectors estabish a linear relation between the vectors: 7vec+6vecc, veca+vecb+vec, 2veca-vecb+vecc, vec-vecb-vecc

If veca, vecb, vecc are non-null non coplanar vectors, then [(veca-2vecb+vecc, vecb-2vecc+veca, vecc-2veca+vecb)]=

If veca, vecb, vecc are three given non-coplanar vectors and any arbitrary vector vecr in space, where Delta_(1)=|{:(vecr.veca,vecb.veca,vecc.veca),(vecr.vecb,vecb.vecb,vecc.vecb),(vecr.vecc,vecb.vecc,vecc.vecc):}|,Delta_(2)=|{:(veca.veca,vecr.veca,vecc.veca),(veca.vecb,vecr.vecb,vecc.vecb),(veca.vecc,vecr.vec ,vecc.vecc):}| Delta_(3)=|{:(veca.veca,vecb.veca,vecr.veca),(veca.vecb,vecb.vecb,vecr.vecb),(veca.vecc,vecb.vecc,vecr.vecc):}|'Delta=|{:(veca.veca,vecb.veca,vecc.veca),(veca.vecb,vecb.vecb,vecc.vecb),(veca.vecc,vecb.vecc,vecc.vecc):}|, "then prove that " vecr=(Delta_(1))/Deltaveca+(Delta_(2))/Deltavecb+(Delta_(3))/Deltavecc