If vecd = gamma(veca xx vecb) + mu(vecb ...

If `vecd = gamma(veca xx vecb) + mu(vecb xx vecc) + v(vecc xx veca)` and `[veca vecb vecc]=1/8`, then `lambda = mu + v` is equal to:

A

`vecd.(veca + vecb +vecc)`

B

`2vecd.(veca+vecb+vecc)`

C

`4vecd.(veca + vecb + vecc)`

D

`8vecd.(veca + vecb + vecc)`

Verified by Experts

The correct Answer is:

C

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