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ABC is isosceles triangle, right angled ...

ABC is isosceles triangle, right angled at A. The resultant of the forces acting along `vec(AB), vec(AC)` with magnitudes `1/(AB)` and `1/(AC)` respectively is the force along `vec(AD)`, where D is the foot of the perpendicular from A on BC. The magnitude of the resultant is:

A

`((AB)(AC))/(AB + AC)`

B

`1/(AB) + 1/(AC)`

C

`1/(AD)`

D

`(AB^(2) + AC^(2))/((AB)^(2)(AC)^(2))`

Text Solution

Verified by Experts

The correct Answer is:
C
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