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If the vectors vecb = tanalpha hati = ha...

If the vectors `vecb = tanalpha hati = hatj+2, sqrt(sinalpha/2hatk)`, and `vecc=tan alpha hati + tan alpha hatj-3/sqrt(sin alpha/2)hatk` are orthogonal and a vector `veca = hati + 3hatj + sin 2alpha hatk` makes an obtuse angle with the z-axis, then the value of `alpha` is

A

`alpha =(4n+1)pi -tan^(-1)2`

B

`alpha =(4n+2)pi - tan^(-)2`

C

`alpha =(4n-1)pi + tan^(-1)2`

D

`alpha (4n-2)pi - tan^(-1)2`

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The correct Answer is:
A, B
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