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In triangle ABC if bar(AC) =u/(|bar u|)...

In triangle ABC if `bar(AC) =u/(|bar u|)-v/(|bar v|) and bar(AC)=(2bar u)/(|baru|)` where `|bar u| != |bar |v|` then

A

1+ cos 2A +cos 2B + cos 2C=0

B

sin A = cos C

C

projection of AC on BC is equal to BC

D

projection of AB on BC is equal to AB

Text Solution

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The correct Answer is:
A, B, C
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