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If the position vectors of the vertices A,B and C of a `triangleABC` are respectively `4hati + 7hatj + 8hatk, 2hati + 4hatk` and `2hati + 5 hatj + 7hatk`,then the positions vector of the point, where the bisector of `angleA` meets BC is:

A

`1/2(4hati + 8hatj + 11hatk)`

B

`1/3(6hati + 13hatj + 18hatk)`

C

`1/4(8hati + 14hatj + 19hatk)`

D

`1/3(6hati + 11hatj + 15hatk)`

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The correct Answer is:
B
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