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Let ABC be a triangle whose circumcenter...

Let ABC be a triangle whose circumcenter is at P, if the positions vectors of A,B,C and P are `veca,vecb,vecc` and `(veca + vecb+vecc)/4` respectively, then the positions vector of the orthocenter of this triangle, is:

A

`-(veca + vecb + vecc)/2`

B

`veca + vecb + vecc`

C

`(veca + vecb + vecc)/2`

D

`vec0`

Text Solution

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The correct Answer is:
C
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