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Let vecalpha = 3hati + hatj and beta= 2h...

Let `vecalpha = 3hati + hatj` and `beta= 2hati - hatj + 3hatk`. If `vecbeta = vecbeta_(1) - vecbeta_(2)`, where `vecbeta_(1)` is parallel to `vecalpha` and `vecbeta_(2)` is perpendicular to `vecalpha`, then `vecbeta_(1) xx vecbeta_(2)` is equal to:

A

`1/2(3hati - 9hatj + 5hatk)`

B

`1/2(-3hati+ 9hatj + 5hatk)`

C

`-3hati + 9hatj + 5hatk`

D

`3hati - 9hatj - 5hatk`

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The correct Answer is:
B
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