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Let O be the origin and let PQR be an ar...

Let O be the origin and let PQR be an arbitrary triangle. The point S is such that `bar(OP)*bar(OQ)+bar(OR)*bar(OS)=bar(OR)*bar(OP)+bar(OQ)*bar(OS)=bar(OQ)*bar(OR)+bar(OP)*bar(OS)` Then the triangle PQR has S as its

A

circumcentre

B

orthocentre

C

incentre

D

centroid

Text Solution

Verified by Experts

The correct Answer is:
B
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