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A tetrahedron is three dimensional figur...

A tetrahedron is three dimensional figure bounded by four non coplanar triangular plane. So a tetrahedron has points A,B,C,D as its vertices, which have coordinates `(x_(1),y_(1),z_(1)) (x_(2), y_(2), z_(2)) , (x _(3), y_(3) , z_(3)) and (x _(4), y _(4), z _(4))` respectively in a rectangular three –dimensional space. Then the coordinates of its centroid are
`((x_(1)+ x_(2) + x _(3) + x_(4))/(4) , (y _(1) + y _(2) + y_(3) + y _(4))/(4), (z_(1) + z_(2) + z_(3)+ z_(4))/(4)).`
The circumcentre of the tetrahedron is the centre of a sphere passing through its vertices. So, the circumcentre is a point equidistant from each of the vertices of tetrahedron.
Let tetrahedron has three of its vertices represented by the points
`(0,0,0) ,(6,-5,-1) and (-4,1,3)` and its centroid lies at the point `(1,-2,5).` Now answer the following questions
The coordinate of the fourth vertex of the tetrahedron is :

A

`(2,-4,16)`

B

`(1,-2,13)`

C

`(-2,4-2)`

D

`(1,-1,1)`

Text Solution

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The correct Answer is:
To find the coordinates of the fourth vertex of the tetrahedron given the coordinates of three vertices and the centroid, we can follow these steps: ### Step 1: Identify the known coordinates The coordinates of the three vertices of the tetrahedron are: - Vertex A: \( A(0, 0, 0) \) - Vertex B: \( B(6, -5, -1) \) - Vertex C: \( C(-4, 1, 3) \) The coordinates of the centroid \( G \) are given as: - \( G(1, -2, 5) \) Let the coordinates of the fourth vertex \( D \) be \( D(x_4, y_4, z_4) \). ### Step 2: Use the centroid formula The formula for the centroid \( G \) of a tetrahedron with vertices \( A, B, C, D \) is given by: \[ G = \left( \frac{x_1 + x_2 + x_3 + x_4}{4}, \frac{y_1 + y_2 + y_3 + y_4}{4}, \frac{z_1 + z_2 + z_3 + z_4}{4} \right) \] Substituting the known values into the centroid formula, we have: \[ G_x = \frac{0 + 6 - 4 + x_4}{4} = 1 \] \[ G_y = \frac{0 - 5 + 1 + y_4}{4} = -2 \] \[ G_z = \frac{0 - 1 + 3 + z_4}{4} = 5 \] ### Step 3: Solve for \( x_4 \) From the equation for \( G_x \): \[ \frac{0 + 6 - 4 + x_4}{4} = 1 \] \[ \frac{2 + x_4}{4} = 1 \] Multiplying both sides by 4: \[ 2 + x_4 = 4 \] Subtracting 2 from both sides: \[ x_4 = 2 \] ### Step 4: Solve for \( y_4 \) From the equation for \( G_y \): \[ \frac{0 - 5 + 1 + y_4}{4} = -2 \] \[ \frac{-4 + y_4}{4} = -2 \] Multiplying both sides by 4: \[ -4 + y_4 = -8 \] Adding 4 to both sides: \[ y_4 = -4 \] ### Step 5: Solve for \( z_4 \) From the equation for \( G_z \): \[ \frac{0 - 1 + 3 + z_4}{4} = 5 \] \[ \frac{2 + z_4}{4} = 5 \] Multiplying both sides by 4: \[ 2 + z_4 = 20 \] Subtracting 2 from both sides: \[ z_4 = 18 \] ### Step 6: Write the coordinates of the fourth vertex Thus, the coordinates of the fourth vertex \( D \) are: \[ D(2, -4, 18) \] ### Final Answer The coordinates of the fourth vertex of the tetrahedron are \( (2, -4, 18) \). ---
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A tetrahedron is a three dimensional figure bounded by four non coplanar triangular plane.So a tetrahedron has four no coplnar points as its vertices. Suppose a tetrahedron has points A,B,C,D as its vertices which have coordinates (x_1,y_1,z_1)(x_2,y_2,z_2),(x_3,y_3,z_3) and (x_4,y_4,z_4) respectively in a rectangular three dimensional space. Then the coordinates of its centroid are ((x_1+x_2+x_3+x_3+x_4)/4, (y_1+y_2+y_3+y_3+y_4)/4, (z_1+z_2+z_3+z_3+z_4)/4) . the circumcentre of the tetrahedron is the center of a sphere passing through its vertices. So, this is a point equidistant from each of the vertices of the tetrahedron. Let a tetrahedron have three of its vertices represented by the points (0,0,0) ,(6,-5,-1) and (-4,1,3) and its centroid lies at the point (1,2,5). The coordinate of the fourth vertex of the tetrahedron is

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