Home
Class 12
MATHS
The equation of the plane containing the...

The equation of the plane containing the line `vecr= veca + k vecb` and perpendicular to the plane `vecr . vecn =q` is :

A

`(vecr -vecb). (vecn xx veca) =0`

B

`(vecr -veca ).{vecn x (veca xx vecb)}=0`

C

`(vecr -veca). (vecn xx vecb)=0`

D

`(vecr-vecb) .{vecn xx (veca xx vecb)}=0`

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Similar Questions

Explore conceptually related problems

The equation of the plane contaiing the lines vecr=veca_(1)+lamda vecb and vecr=veca_(2)+muvecb is

The equation of the line throgh the point veca parallel to the plane vecr.vecn=q and perpendicular to the line vecr=vecb+tvecc is (A) vecr=veca+lamda (vecnxxvecc) (B) (vecr-veca)xx(vecnxxvecc)=0 (C) vecr=vecb+lamda(vecnxxvecc) (D) none of these

The vector equation of a plane which contains the line vecr=2hati+lamda(hatj-hatk) and perpendicular to the plane vecr.(hati+hatk)=3 is

The line vecr= veca + lambda vecb will not meet the plane vecr cdot n =q, if

The equation of the plane containing the line vecr=hati+hatj+lamda(2hati+hatj+4hatk) is

Assertion: vecAxxvecB is perpendicular to both vecA+vecB as well as vecA-vecB . Reason: vecA+vecB as well as vecA-vecB lie in the plane containing vecA and vecB , but vecAxxvecB lies perpendicular to the plane containing vecA and vecB

Find the equation of the plane through the point hati+4hatj-2hatk and perpendicular to the line of intersection of the planes vecr.(hati+hatj+hatk)=10 and vecr.(2hati-hatj+3hatk)=18.

The equation of the plane which contains the origin and the line of intersectio of the plane vecr.veca=d_(1) and vecr.vecb=d_(2) is

The plane vecr cdot vecn = q will contain the line vecr = veca + lambda vecb if

The equation of the line of intersetion of the planes vecr.vecn=q,vecr.vecn\'=q\' and pasing through the point veca is (A) vecr=veca+lamda(vecn-vecn\') (B) vecr=veca+lamda(vecnxxvecn\') (C) vecr=veca+lamda(vecn+vecn\') (D) none of these