For a regular polygon of `n` sides having side length `'a'` then find area,circumradius,perimeter,inradius

The area of a regular polygon of n sides is (where r is inradius, R is circumradius, and a is side of the triangle (a) (n R^2)/2sin((2pi)/n) (b) n r^2tan(pi/n) (c) (n a^2)/4cotpi/n (d) n R^2tan(pi/n)

The area of a regular polygon of n sides is (where r is inradius, R is circumradius, and a is side of the triangle) (n R^2)/2sin((2pi)/n) (b) n r^2tan(pi/n) (n a^2)/4cotpi/n (d) n R^2tan(pi/n)

The area of a regular polygon of n sides is (where r is inradius, R is circumradius, and a is side of the triangle (a) (n R^2)/2sin((2pi)/n) (b) n r^2tan(pi/n) (c) (n a^2)/4cotpi/n (d) n R^2tan(pi/n)

The area of a regular polygon of n sides is (where r is inradius, R is circumradius, and a is side of the triangle) (n R^2)/2sin((2pi)/n) (b) n r^2tan(pi/n) (n a^2)/4cotpi/n (d) n R^2tan(pi/n)

The area of a regular polygon of n sides is (where r is inradius,R is circumradius,and a is side of the triangle) (nR^(2))/(2)sin((2 pi)/(n))(b)nr^(2)tan((pi)/(n))(na^(2))/(4)cot(pi)/(n)(d)nR^(2)tan((pi)/(n))

If the regular octagon having side length is 14.5m, then its perimeter is ?

The area of the circle and the area of a regular polygon of n sides and the perimeter equal to the circle are in the ratio of

The area of a regular polygon of in-sides inscribed in a circle is to that of the same number of sides circumsending the same circle is 3:4 then n=