The general value of `theta` satisfying the equation `tan^2theta+sec2theta=1` is_____

Explanation

`tan^2theta + sec2theta= 1`

`=>tan^2 theta +1/(cos2theta) = 1`

`=>tan^2 theta +(1+tan^2theta)/(1-tan^2theta) = 1`

Let `tan theta = x`

Then, our equation becomes,

`=>t +(1+t)/(1-t) =1 `

`=>t - t^2 +1 +t = 1-t`

`=>t^2 - 3t = 0`

...