The area bounded by the curve `f(x)=x+sinx` and its inverse function between the ordinates `x=0a n dx=2pi` is `4pis qdotu n i t s` (b) `8pis qdotu n i t s` `4s qdotu n i t s` (d) `8s qdotu n i t s`

The area bounded by the curves y=sinx between the ordinates x=0,\ x=pi and the x-axis is 2\ s qdotu n i t s b. 4\ s qdotu n i t s c. 3\ s qdotu n i t s d. 1\ s qdotu n i t s

The area of the region enclosed between the curves x=y^2-1a n dx=|y|sqrt(1-y^2) is 1s qdotu n i t s (b) 4/3s qdotu n i t s 2/3s qdotu n i t s (d) 2s qdotu n i t s

The area bounded by the curves y=(log)_e xa n dy=((log)_e x)^2 is e-2s qdotu n i t s (b) 3-es qdotu n i t s es qdotu n i t s (d) e-1s qdotu n i t s

Let f(x)=x^3+3x+2a n dg(x) be the inverse of it. Then the area bounded by g(x) , the x-axis, and the ordinate at x=-2a n dx=6 is 1/4s qdotu n i t s (b) 4/3s qdotu n i t s 5/4s qdotu n i t s (d) 7/3s qdotu n i t s

What is the area of the shaded region? (FIGURE) 32-4 pi s qdotu n i t s (b) 32-8 pi s qdotu n i t s (c) 16-4 pi s qdotu n i t s (d) 16-8 pi s qdotu n i t s

Let f(x)=x^3+3x+2a n dg(x) be the inverse of it. Then the area bounded by g(x) , the x-axis, and the ordinate at x=-2a n dx=6 is (a) 9/4s qdotu n i t s (b) 4/3s qdotu n i t s (c) 5/4s qdotu n i t s (d) 7/3s qdotu n i t s

Let f(x)=x^3+3x+2 and g(x) be the inverse of it. Then the area bounded by g(x) , the x-axis, and the ordinate at x=-2a n dx=6 is (a) 9/2s qdotu n i t s (b) 4/3s qdotu n i t s (c) 5/4s qdotu n i t s (d) 7/3s qdotu n i t s

The area bounded by the curves y=sin^(-1)|sinx|a n dy=(sin^(-1)|sinx|^2,w h e r e0lt=xlt=2pi, is 1/3+(pi^2)/4 s qdotu n i t s (b) 1/6+(pi^3)/8s qdotu n i t s 2s qdotu n i t s (d) none of these

The area bounded by the curves y=sin^(-1)|sinx|a n dy=(sin^(-1)|sinx|^2,w h e r e0lt=xlt=2pi, is 1/3+(pi^2)/4 s qdotu n i t s (b) 1/6+(pi^3)/8s qdotu n i t s 2s qdotu n i t s (d) none of these

The area bounded by the curve y^2=8x\ a n d\ x^2=8y is (16)/3s qdotu n i t s b. 3/(16)s qdotu n i t s c. (14)/3s qdotu n i t s d. 3/(14)s qdotu n i t s