[" A "10" for all natural number "n],[" B "10" for odd natural number "n],[" C "10" for even natural number "n" ,is divisible by "],[D" .None of these "]

The sum of n odd natural numbers is

A ={set of odd natural numbers}, B={sets of even natural numbers}, then A and B are

The S.D. of first n odd natural numbers is:

In n is a natural number,n(n + 1)(n + 2) will always divisible by

Form the bicoditional statement phArrq . Where p: Natural number n is odd. q: Natural number n is not divisible by 2.

The difference between the sum of squares of first n natural numbers and the sum of first n natural numbers is always divisible by 2.

If n is an odd natural number greater than 1 then the product of its successor and predecessor is an odd natural number (b) is an even natural number can be even or odd (d) None of these

If n is an even natural number, then the largest natural number by which n(n + 1)(n + 2) is divisible, is

A = sum of first 10 natural numbers, B = sum of squares of first 10 natural numbers, C = sum of cubes of first 10 natural numbers, D = sum of first 10 even natural numbers, then increasing order of A,B,C,D