Property 7 There are no natural numbers `p and q` such that `p^2 = 2q^2`.

r, s, t are prime numbers and p, q are natural numbers such that LCM of p, q is r^(2)" "s^(4)" "t^(2) , then the number of ordered pairs (p,q) is

If p,q,r,s are natural numbers such that p>=q>=r If 2^(p)+2^(q)+2^(r)=2^(s) then

If p and q are positive real number such that p^(2) + q^(2) = 1 , then the maximum value of (p + q) is :

If p and q are positive real numbers such that p^2+ q^2=1 , then the maximum value of (p +q) is :

If p and q are positive real numbers such that p^(2)+q^(2)=1 then find the maximum value of (p+q)

if p and q are positive real numbers such that p^(2)+q^(2)=1 then find the maximum value of (p+q)

If p and q are positive real numbers such that p^2+q^2=1 , then the maximum value of p+q is