If the base angles of triangle are `((22)/(12))^@` and `(112 1/2)^@` , then prove that the altitude of the triangle is equal to `1/2` of its base.

Explanation

We can create a diagram with the given details.

Please refer to video to see the diagram.

`/_BAC = 180-112.5-22.5 = 45^@`

`/_ACL = 180-112.5 = 67.5^@`

Now, in `Delta ABC`,

From sine law,

`(BC)/(sin45^@) =( AC)/(sin22.5^@)`

`=>AC = (BC sin22.5^@)/sin45^@`

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