`(2x^(3)+x^(2)-5)/(x^(4)-25)=(Ax+B)/(x^(2)-5)+(Cx+D)/(x^(2)+5)``rArr(A,B,C,D)`

If (1)/(x^(4)+x^(2)+1)=(Ax+B)/(x^(2)+x+1)+(Cx+D)/(x^(2)-x+1) then

If (1)/(x^(4)+x^(2)+1)=(Ax+B)/(x^(2)+x+1)+(Cx+D)/(x^(2)-x+1) then C+D=

If (1)/(x^(4)+x^(2)+1)=(Ax+B)/(x^(2)+x+1)+(Cx+D)/(x^(2)-x+1) then C+D

The factors of x^(4)+x^(2)+25 are (a)(x^(2)+3x+5)(x^(2)-3x+5)(b)(x^(2)+3x+5)(x^(2)+3x-5)(c)(x^(2)+x+5)(x^(2)-x+5) (d) none of these

int((4e^(x)-25)/(2e^(x)-5))dx=Ax+B(log)/(2e^(x))-(5)/(+c)

If (x^(3))/((x-1)(x-2))=Ax+B+(C )/(x-1)+(D)/(x-2) , then A,B,C and D , respectively are ____________.

If (3^(2x-8))/(225)=(5^(3))/(5^(x)), then x=2( b) 3(c)5(d)4

If x^(3)=(1)/(x^(3))=14, then x-(1)/(x)=5 (b) 4(d)3(d)2

The biquadratic equation, two of whose roots are 1+i , 1-sqrt(2) is A) x^(4)-4x^(3)+5x^(2)-2x-2=0 B) x^(4)-4x^(3)-5x^(2)+2x+2=0 C) x^(4)+4x^(3)-5x^(2)+2x-2=0 D) x^(4)+4x^(3)+5x^(2)-2x+2=0

{:( "Column" A ,, "Column" B) , ("If" a^(2) - b^(2) = 16 "and" a- b = 2 "," "then" a + b,, "(a)" 3x^(2) - x - 11), ("The degree of " (x-a) (x-b) (x - c) (x-d) ,, "(b)" 3x^(2) - x + 5), (4x^(2) + 20xy + 25y^(2) ,, (c) 8), ((5x^(2) + 7x -3)- (2x^(2) + 8x -8) ,, (d) 4), (,, (e) (4x + 5y) (x+ 5y)), (,,(f) (2x + 5y)^(2)):}