If X is a poisson variate with P(x=0)=0.8 then the variance of x is

If X is a poisson variety with P(x=0)=0.8 then the variance of x is (A) log_(e)^(20) log_(10)^(20) (B) ( C) log((5)/(4)) (D) 0

" If "x" is a Poisson variate such that "P(x=0)=0.1" ,"P(x=2)=0.2" then the parameter "lambda" is "

If X is a Poisson variate such that P(X=3)=P(X=2) , then P(X=4)=

If X is binomial variate with E(X)=5 and variance 4. The parameters of the distribution are

If x is binomial variate with E(x)=5 and variance 4. The parameters of the distribution are

If X is a random poisson variate such that E(X^2)=6 then E(X)=

If X is a binomial variate with mean 6 and variance 2, then the value of P(5leXle7) is

For a binomial variate X with n=6, if P(X=2)=9,P(X=4) , then its variance is

If X is a poisson variable such that 2P(X=0)+P(X=2)=2P(X=1) then E(X)=