A transverse wave is represented by the equation y=2sin(30t-40x) and the measurements of distances are in meters then the velocity of propagation is

A wave is represented by the equation y=7 sin {pi (2t -2x)} here x is in metres and t in seconds. The velocity of the wave is

The transverse wave represented by the equation y = 4 "sin"((pi)/(6)) "sin"(3x - 15 t) has

A wave is represented by the equation : y=a sin (0.01x-2t) where a and x are in cm . velocity of propagation of wave is

A transverse wave is represented by the equation y=y_0sin.(2pi)/(lamda)(vt-x) For what value of lamda , the maximum particle velocity equal to two times the wave velocity?

A transverse wave is described by the equation y=A sin [2pi(ft-x//lambda)] . The maximum particle velocity is equal the wave velocity if :

A wave is represented by the equation y=0.5 sin (10 t-x)m . It is a travelling wave propagating along the + x direction with velocity

Transverse wave is described by the equation y=y_0 sin 2pi (ft-x/lambda) .The maximum particle velocity is twice the wave velocity if wavelength is____

The linear density of a vibrating string is 10^(-4) kg//m . A transverse wave is propagating on the string, which is described by the equation y=0.02 sin (x+30t) , where x and y are in metres and time t in seconds. Then tension in the string is