A ray along `x-y-6=0` incidents on `x`-axis at `(6,0)` and the reflected ray touches a circle with centre at origin having radius

Find the equation of the circle touching : x-axis at the origin and having radius 10

A circle has its centre on the y-axis and passes through the origin, touches anotgher circle with centre (2,2) and radius 2, then the radius of the circle is

A light ray gets reflected by y-axis. If the point of incidence is (0,-2) and reflected ray touches the circle x^(2) + y^(2) - 2x -2y +1=0 , then the equationof incident ray is

If the length of the normal for each point on a curve is equal to the radius vector,then the curve (a) is a circle passing through origin (b) is a circle having centre at origin and radius 0 (c) is a circle having centre on x-axis and touching y-axis (iv) is a circle having centre on y-axis and touching x-axis

A ray of light passing through (a,0) is incident on the parabola y^(2)=4ax at (a,2a) and get reflected by it. The reflected ray in along the line.

A ray of light travelling along the line x+y=1 is incident on the x-axis and after refraction it enters the other side of the x-axis by turning 30^0 away from the x-axis. The equation of the line along which the refracted ray travels is

In the given figure, two mirrors X and Y are situated at an angle of 60^(@) with each other and a ray of light is incident on mirror X at an angle of 50^(@) . When the ray is reflected by the mirror Y, then what is angle of reflection at this mirror?

The incident ray is along the line 3x-4y-3=0 and the reflected ray is along the line 24x+7y+5=0. Find the equation of mirrors.

Statement I A ray of light incident at the point (-3,-1) gets reflected from the tangent at (0,-1) to the circle x^(2)+y^(2)=1 . If the reflected ray touches the circle, then equation of the reflected ray is 4y-3x=5 Statement II The angle of incidence = angle of reflection i.e. anglei=angler ,