Gravitation - Continuous Mass Distribution (2)

Questions|Important Points About Centre Of Mass|Centre Of Mass Of Continuous Mass Distribution|Centre Of Mass Of Uniform Rod

Centre Of Mass Of A Continuous Mass Distriubution

The gravitational field due to a mass distribution is E=(A)/(x^(2)) in x-direction. Here, A is a constant, Taking the gravitational potential to be zero at infinity, potential at x is

Gravitational Mass

The gravitational field due to a mass distribution is given by E=-K//x^3 in x-direction. Taking the gravitational potential to be zero at infinity, find its value at a distance x .

On the x - axis and at a distance x from the origin, the gravitational field due to a mass distribution is given by (Ax)/((x^2+a^2)^(3//2)) in the x - direction. The magnitude of gravitational potential on the x - axis at a distance x, taking its value to be zero at infinity , is :

The gravitational field due to a mass distribution is given by vec(l)=(k)/(x^(2))hat(i) , where k is a constant. Assuming the potential to be zero at infinity, find the potential at a point x = a.

The gravitational field due to a mass distribution is given by l=kx^(-3//2) in x-direction, where k is a positive constant. Taking potential to be zero at infinity, find its value at a distance x.

Questions|Centre Of Mass Of Continous Mass Distribution|Cavity Problems