find the extreme values of `(7x^2)+(8xy)+(y^2)` subject to the condition `(x^2)+(y^2)=1`

Find the minimum and maximum value of f(x,y)=7x^(2)+4xy+3y^(2) subjected to x^(2) +y^(2) =1

The solution of the differential equation (dy)/(dx)=xy+2y subject to the condition y=1 at x=1 is -

Find the value of xy+y^2x if x=1, y=0

The maximum value of xy subject to x+y =7 is

If x:y= 3: 4, then the value of (5x - 2y)/(7x + 2y) =

Find the value of: xy+y^2x , for x=-1 and y=1

If x-y=7 and xy=9, then find the value of (x^2+y^2)

Find graphically the minimum value of Z=5x+7y , subject to the constraints given below: 2x+y ge 8, x +2y ge 0 and x, y ge 0