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Solve cos2x >|sinx|,x in (pi/2,pi)...

Solve `cos2x >|sinx|,x in (pi/2,pi)`

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Solve cos 2x=|sin x|, x in (-pi/2, pi) .

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Knowledge Check

  • If f(x)={(x+a sqrt(2) sinx"," ,0 lt x lt (pi)/(4)),(2x cotx+b",",(pi)/(4) le x le (pi)/(2)),(a cos 2x-b sinx",", (pi)/(2) lt x le pi):} is continuous at x=(pi)/(4) , then a - b is equal to

    A
    `(pi)/(2)`
    B
    0
    C
    `(1)/(4)`
    D
    `(pi)/(4)`

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