[int_(0)^(16n^(2))(cos(pi)/(2)[(x pi)/(n)])dx],[" G.I.F) is equal to "]

int_(0)^(16n^(2)//pi) "cos" (pi)/(2)[(xpi)/(n)] dx is equal to

int_(0)^(16n^(2)//pi) "cos" (pi)/(2)[(xpi)/(n)] dx is equal to

int_(0)^(16n^(2)//pi) "cos" (pi)/(2)[(xpi)/(n)] dx is equal to

int_(0)^(2pi) (xsin^(2n)x)/(sin^(2n)x+cos^(2n)x)dx,n gt 0 , is equal to

int_(-pi)^( pi)sin x[f(cos x)]dx is equal to

If I_(n)=int_(0)^( pi)e^(x)(sin x)^(n)dx, then (I_(3))/(I_(1)) is equal to

If I_(n)=int_(0)^(pi) e^(x)(sinx)^(n)dx , then (I_(3))/(I_(1)) is equal to

If A=int_(0)^( pi)(sin x)/(x^(2))dx, then int_(0)^((pi)/(2))(cos(2x))/(x)dx, is equal to:

For any n in N,int_(0)^( pi)(sin^(2)(nx))/(sin^(2)x)dx is equal to

The value of I=int_(0)^((pi)/(4))(tan^(n+1)x)dx+(1)/(2)int_(0)^((pi)/(2))tan^(n-1)((x)/(2))dx is equal to-