`5 19/16- 3 2/5`

The eccentricity of the ellipse 2x^(2)+16y^(2)=400 is 3/5 b.1/3 c.2/5 .1/5

Find the value of ^(20)C_16 - ^(19)C_16 = ((20!)/(4! * 16!)) - ((19!)/(3! * 16!))

The simplified value of 2 1/3 of (3/5 div 2/9)- (4 2/5+19/20 div 1/2) is : 2 1/3 of (3/5 div 2/9)- (4 2/5+19/20 div 1/2) का सरलीकृत मान है:

Find using distributivity : {9/16 × 3}+{9/16 xx (-19)}

Workout : 7.4-2.19-0.456 - 3.5

(16(2)/(5)-12(1)/(15))-:3(4)/(81)=?( a) 1(9)/(19) (b) 1(9)/(13)(c)2(8)/(13) (d) 3(2)/(19) (e) None of these

Let us multiply the follwing (i) 2/3 × 5/6 (ii) 7/8 × 3/10 (iii) 19frac(3)(4) × 1/7 (iv) 16/5 × 27/7

The simplified value of 2 1/3 of (3/5 div 2/9)-(4 2/5+19/20 div 1/2) is : 2 1/3 of (3/5 div 2/9)-(4 2/5+19/20 div 1/2) का सरलीकृत मान है

5 3/x xx 3 1/2=19 then x=