` sec^2 theta =1-tan 2 theta`

Find the general solutions of the following equations: sec^2(2theta) = 1-tan2theta

Prove that- sec^2theta-1-tan^2theta=0

Solve the following equations : i) tantheta=cottheta , ii) cos2theta=2sin^(2)theta iii) tan3theta=-sqrt(3) , iv) sin2theta-costheta=0 v) sec^(2)2theta=1-tan2theta

Solve the following equations : i) tantheta=cottheta , ii) cos2theta=2sin^(2)theta iii) tan3theta=-sqrt(3) , iv) sin2theta-costheta=0 v) sec^(2)2theta=1-tan2theta

Show that (1)/(3) lt (sec^(2) theta - tan theta)/( sec^(2) theta+ tan theta) lt3 .

Prove that (sintheta-costheta+1)/(sintheta+costheta-1)=1/(sectheta-tantheta) , using the identity sec^2theta=1+tan^2theta

Find the values of the following expression. (sec^2theta-1)/tan^2theta =?

(2sin theta tan theta(1-tan theta)+2sin theta sec^(2)theta)/((1+tan theta)^(2))=(2sin theta)/(1+tan theta)

For theta_(1), theta_(2), ...., theta_(n) in (0, pi/2) , if In (sec theta_(1)-tan theta_(1))+ "In" (sec theta_(2)-tan theta_(2))+...+"In" (sec theta_(n)-tan theta_(n))+ "ln" pi=0 , then the value of cos((sec theta_(1)+ tan theta_(1))(sec theta_(2)+tan theta_(2))....(sec theta_(n)+tan theta_(n))) is equal to