General solution of `sin^2x-5sinxcosx-6cos^2x=0` is `x=npi-pi/4,n in Z` only n`pi+tan^(-1)6,n in Zon l y` both (a) and (b) none of these

Explanation

`sin^2x/cos^2x-(5sinxcosx)/(cos^2x)-(6cos^2x)/(cos^2x)=0`

`tan^2x-5tanx-6=0`

`tan^2x-6tanx+tanx-6=0`

`tanx(tanx-6)+1(tanx-6)=0`

`(tanx+1)(tanx-6)=0`

`tanx=-1`

`x=npi-pi/4`

`tanx=6`

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