The area bounded by `y = f(x),` x-axis and the line `y = 1,` where `f(x)=1+1/x int_1^xf(t)dt` is

Area bounded by f(x)=(x^(2)-1)/(x^(2)+1) and the line y = 1 is

Area bounded by f(x)=(x^(2)-1)/(x^(2)+1) and the line y = 1 is

Area bounded by f(x)=(x^(2)-1)/(x^(2)+1) and the line y = 1 is

Find a continuous function f, where (x^(4)-4x^(2))lef (x) le (2x^(2)-x^(3)) such that the area bounded by y=f(x), y=x^(4)-4x^(2), the y-axis, and the line x=t," where "(0letle2) is k times the area bounded by y=f(x),y=2x^(2)-x^(3), y-axis, and line x=t("where "0le t le 2).

Find the continuous function f where (x^(4)-4x^(2))<=f(x)<=(2x^(2)-x^(3)) such that the area bounded by y=f(x),y=x^(4)-4x^(2) then y-axis,and the line x=t, where (0<=t<=2) is k xx the area bounded by y=f(x),y=2x^(2)-x^(3),y-axis, and line x=t(where0<=t<=2).

If the area bounded by y=f(x), the x -axis, the y-axis and x=t(t>0) is t^(2), then find f(x) .

The area bounded by the curve y=f(x), the x -axis and x=1 and x=c is (c-1)sin(3c+4) Then f(x) is

The area bounded by the curve y=f(x) (where f(x)>=0) ,the co-ordinate axes & the line x=x_(1) is given by x_(1).e^(x_(1)). Therefore f(x) equals