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In a cyclic quadrilateral PQRS, PQ= 2 un...

In a cyclic quadrilateral PQRS, PQ= 2 units, QR= 5 units, RS=3 units and `/_P Q R=60^0,` then what is the measure of SP?

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`In/_PQR`
`(cosA=(b^2+c^2-a^2)/(2bc))`
`cos60=(2^2+5^2-PR^2)/(2*2*5)`
`PR^2=19`
`In/_PRS`
`PR^2=3^2+x^2-2*3*x*cos120`
`19=9+x^2+3x`
`x^2+3x-10=0`
...
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