Three circles touch each other externally. The tangents at their point of contact meet at a point whose distance from a point of contact is 4. Then, the ratio of their product of radii to the sum of the radii is

Three circles touch one-another externally. The tangents at their point of contact meet at a point whose distance from a point contact is 4. Then, the ratio of the product of the radii of the sum of the radii of circles is

Three circles with radius r_(1), r_(2), r_(3) touch one another externally. The tangents at their point of contact meet at a point whose distance from a point of contact is 2 . The value of ((r_(1)r_(2)r_(3))/(r_(1)+r_(2)+r_(3))) is equal to

Three circles whose radii are a,b and c and c touch one other externally and the tangents at their points of contact meet in a point. Prove that the distance of this point from either of their points of contact is ((abc)/(a+b+c))^(1/2) .

Three circles are such that each touch the other two externally.The common tangents are concurrent at 'p'.The length of the tangent to each circle is P.The ratio of the product of their radii to sum of their radii is

If two circles touch each other (internally or externally); the point of contact lies on the line through the centres.

Three circles touch each other externally. The distance between their centre is 3 cm, 4 cm and 5 cm. Find the radii of the circles :