41.Self energy of conducting sphere of radius r carrying charge is (1) `(Q^(2))/(8 pi epsilon_(0)(r)` (2) `(Q^(2))/(4 pi epsilon_(0)(r)` (3) `(Q^(2))/(6 pi epsilon_(0)(r)` (4) `(Q^(2))/(2 pi epsilon_(0)(r)`

There are three charges Q_(1) columb Q_(2) columb and Q_(3) columb. Q_(2) and Q_(3) are fixed at positive (0,0) and (30,0) respectively.Now Q_(1) moves in circular path in x -y plane of radius 40 m with help of external agent starting from (0 ,40) about origin then work done by external agent is till Q_(1) crosses x axis (40, 0) given co-ordinates are in centimeters: (1) (Q_(1)Q_(3))/(4 pi epsilon_(0)) joule (2) (Q_(1)Q_(3))/(2 pi epsilon_(0)) joule (3) (2Q_(1)Q_(3))/(pi epsilon_(0)) joule (4) (2Q_(1)(Q_(2)+Q_(3)))/(pi epsilon_(0)) joule

There are three charges Q_(1) columb Q_(2) columb and Q_(3) columb. Q_(2) and Q_(3) are fixed at positive (0 0) and (30 0) respectively.Now Q_(1) moves in circular path in x -y plane of radius 40 cm with help of external agent starting from (0 40) about origin then work done by external agent is till Q_(1) crosses x axis (40 0) given co-ordinates are in centimeters: 1) (Q_(1)Q_(3))/(4 pi epsilon_(0)) joule 2) (Q_(1)Q_(3))/(2 pi epsilon_(0)) joule 3) (2Q_(1)Q_(3))/(pi epsilon_(0)) joule 4) (2Q_(1)(Q_(2)+Q_(3)))/(pi epsilon_(0)) joule

A charge q_(1) is placed at the centre of a spherical conducting shell of radius "R" .Conducting shell has a total charge q_(2) .Electrostatic potential energy of the system is (A) (q_(1)^(2)+2q_(1)q_(2))/(8 pi varepsilon_(0)R) (B) (q_(2)^(2)+2q_(1)q_(2))/(8 pi varepsilon_(0)R) (C) (q_(1)^(2)+q_(1)q_(2))/(8 pi varepsilon_(0)R) (D) (q_(2)^(2)+q_(1)q_(2))/(8 pi varepsilon_(0)R)

Find the dimension of (1)/((4pi)epsilon_(0))(e^(2))/(hc))

The dimesions of (mu_(0) epsilon_(0))^(-1//2) are

The dimensions of (1)/(epsilon_(0))(e^(2))/(hc) are

The vector form of Coulomb's law is (A) vec F=(1)/(4 pi epsilon_(0))*(q_(1)q_(2))/(|vec r|^(3))vec r (B) vec F=(1)/(4 pi epsilon_(0))*(q_(1)q_(2))/(|vec r|^(3)) (C) vec F=(1)/(4 pi epsilon_(0))*(q_(1)q_(2))/(r^(2))vec r (D) vec F=(1)/(4 pi epsilon_(0))*(q_(1)q_(2))/(r)vec r

The vector form of Coulomb's law is (A) vec F=(1)/(4 pi epsilon_(0))*(q_(1)q_(2))/(|vec r|^(3))vec r (B) vec F=(1)/(4 pi epsilon_(0))*(q_(1)q_(2))/(r^(3)) (C) vec F=(1)/(4 pi epsilon_(0))*(q_(1)q_(2))/(r^(2))vec r (D) vec F=(1)/(4 pi epsilon_(0))*(q_(1)q_(2))/(r)vec r

Using the concept of energy density , show that the total energy stored by a shell of radius R and charge Q is (Q^(2))/( 8 pi epsilon_(0)R)