Two particles of mass m and 2m carry a charge q each.Initially the heavier particle is at rest on a smooth horizontal plane and the other is projected along the plane directly towards the first from a distance d with speed u .If the closest distance of approach is `(3q^(2)d)/(nq^(2)+4 pi e_(0)u^(2)d)` then find the value of n .

Q:6DTQ Two particles of mass m and 2m carry a charge q each.Initially the heavier particle is at rest on a smooth horizontal plane and the other is projected along the plane directly towards the first from a distance d with speed u.If the closest distance of approach is (3q^(2)d)/(nq^(2)+4 pi varepsilon_(0)u^(2)d) then find the value of n .

Two identical particles of mass m carry a charge Q , each. Initially one is at rest on a smooth horizontal plane and the other is projected along the plane directly towards first particle from a large distance with speed v. The closest distance of approach be .

Two particle m and 3m carry charge q each.Initially the heavier particle is at rest on a smooth horizontal plane and other is projected towards the first from far- off distance with speed V_(0) .Distance of closest approach is

Two particle m and 3m carry charge q each.Initially the heavier particle is at rest on a smooth horizontal plane and other is projected towards the first from far-off distance with speed V_(0) .Distance of closest approach is

A charge "Q" of mass "m" is at rest on a smooth horizontal plane.Another identical particle is projected with a velocity v towards it from long distance then

Two charged particles of masses m and 2m are placed distane d apart on a smooth horizontal table. Because of their mutual attraction, they move towards each other and collide. Where will the collision occure with respect to the initial positions?

Two electric charges q and - 2 q are placed at a distance 6 m apart on a horizontal plane. Find the locus of point on this plane where the potential has a value zero. .

Two particles of mass m_(1) and m_(2) are approaching towards each other under their mutual gravitational field. If the speed of the particle is v, the speed of the center of mass of the system is equal to :

A charged particle of mass m and charge q is kept initially at rest on a frictionless surface. Another charged particle of mass 4m and charge 2q starts moving with velocity v towards it. Calculate the distance of the closest approach for both the charged particles.

Two particles of mass M and 2M are at a distance D apart. Under their mutual force of attraction they start moving towards each other. The acceleration of their centre of mass when they are D/2 apart is :