`tan^(-1) [(a+b tan x)/(b-a tan x)]`

tan^(-1)( (a+b tan c)/ (b-a tan x) )

int(dx)/(a+b tan x)dxa+b tan x

Simplify tan^(-1)[(a cos x-b sin x)/(b cos x+a sin x)], if (a)/(b)tan x>-1

int(1)/(1-sin^(4)x)dx=(1)/(a sqrt(b))+tan^(-1)(sqrt(a)tan x)+(1)/(b)tan x+C then (a)/(b) is equal to

" tan " ((pi)/(4) -x) =(1 - tan x)/( 1+ tan x)

" tan " ((pi)/(4) +x) =(1 + tan x)/(1-tan x)

For all values of A and Btan(A+B)=(tan A+tan B)/(1-tan A tan B) and tan(A-B)=(tan A-tan B)/(1+tan A tan B)

tan(A+B)=(tan A+tan B)/(1-tan A tan B)

If A and B are acute angles such that tan A=(1)/(2),tan B=(1)/(3) and tan(A+B)=(tan A+tan B)/(1-tan A tan B), find A+B