Two capacitors `2 mu` F and `6 mu` F are in series the effective capacitance of the system is `mu` F will be .....??

The minimum number of capacitors (each of capacitance 2 mu F ) required to get an effective capacitance of 9 mu F is?

Two capacitors of 2mu F and 3mu F are connected in series. The potential at point A is 1000 volt and the outer plate of 3mu F capacitor is earthed. The potential at point B is

Consider two capacitors : C_(1) = 10 mu C and C_(2) = 40 mu F . What is the equivalent capacitance if the two are connected. (1) in parallel ? (2) in series ? (3) If the two are connected in series to a 9.0 volt battery what are the charges Q_(1) and Q_(2) stored on the two capacitors ?

Three capacitors of 3 mu F,2 mu F and 6 mu F are connected in series. When a battery of 10 V is connected to this combination then charge on 3 mu F capacitor will be.

Three capacitors each of capacitance 1 mu F are connected in parallel.To this combination,a fourth capacitor of capacitance 1 mu F is connected in series.The resultant capacitance of the system

Two capacitors of capacites 1 mu F and C mu F are connected in series and the combination is charged to a potential difference of 120 V . If the charge on the combination is 80 muC , the energy stored in the capacitor C in micro joules is :

Two capacitors of capacitance 10 mu F and 20 muF are connected in series with a 6 V battery. If E is the energy stored in 20 muF capacitor what will be the total energy supplied by the battery in terms of E.

The ratio of resultant capacities when three capacitors of 2 mu F , 4 mu F and 6 mu F are connected first in series and in parallel ...?