The root of the equation `2(1 + i) x^2-4(2-i) x-5-3 i = 0,` where `i = sqrt(-1),` which has greater modulus is

The root of the equation 2(1+i)x^(2)-4(2-i)x-5-3i=0, where i=sqrt(-1), which has greater modulus is

If alpha and beta are the complex roots of the equation (1+i)x^(2)+(1-i)x-2i=o where i=sqrt(-1) , the value of |alpha-beta|^(2) is

3+4i is a root of the equation x^(2)+px+q=0 then

Fill in the blank : If 1+ i is a root of the equation ix^2-3x+p = 0 where i= sqrt-1 then the other root is ………..