If `(sinx)/a=(cosx)/b=(tanx)/c=k ,` then `b c+1/(c k)+(a k)/(1+b k)` is equal to `k(a+1/a)` (b) `1//k(a+1/a)` `1/(k^2)` (d) `a/k`

Explanation

To solve the problem, we start with the given equations:

\[ \frac{\sin x}{a} = \frac{\cos x}{b} = \frac{\tan x}{c} = k \]

From these equations, we can express \(\sin x\), \(\cos x\), and \(\tan x\) in terms of \(k\):

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